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4x^2+48x-26837.3476=0
a = 4; b = 48; c = -26837.3476;
Δ = b2-4ac
Δ = 482-4·4·(-26837.3476)
Δ = 431701.5616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-\sqrt{431701.5616}}{2*4}=\frac{-48-\sqrt{431701.5616}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+\sqrt{431701.5616}}{2*4}=\frac{-48+\sqrt{431701.5616}}{8} $
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